Résoudre une équation du type e^u(x)=k en utilisant la fonction logarithme Exercice

S = \left\{ \dfrac{1+ \ln\left(3\right)}{4}\right\}

S = \left\{ \dfrac{-1+ \ln\left(3\right)}{4}\right\}

S = \left\{ 1\right\}

S = \left\{ \dfrac{1+ e^3}{4}\right\}

S= \left\{ \dfrac{2-2 \ln\left(2\right)}{5} \right\}

S = \left\{ \dfrac{-2}{5}\right\}

S = \left\{ \dfrac{2- e^4}5{}\right\}

S = \left\{ \dfrac{ \ln4-2}{5}\right\}

S = \left\{ \dfrac{2 \ln\left(3\right)}{7}\right\}

S = \left\{ \dfrac{9}{7}\right\}

S = \left\{ \dfrac{e^9}{7}\right\}

S = \left\{ \dfrac{7}{2 \ln\left(3\right)}\right\}

S = \left\{ 1-\sqrt{1+\ln\left(5\right)};1+\sqrt{1+\ln\left(5\right)} \right\}

S = \left\{ 1-\sqrt{1+e^5};1+\sqrt{1+e^5} \right\}

S =\left\{ 1- \sqrt{6};1+\sqrt{6}\right\}

S = \left\{ 1-\sqrt{-1+\ln\left(5\right)};-1+\sqrt{1+\ln\left(5\right)} \right\}

S=\left\{ \dfrac{-1-\sqrt{1+4\ln\left(2\right)}}{2};\dfrac{-1+\sqrt{1+4\ln\left(2\right)}}{2} \right\}

S=\left\{ \dfrac{-1-\sqrt{1+4e^2}}{2};\dfrac{-1+\sqrt{1+4e^2}}{2} \right\}

S=\left\{ \dfrac{1-\sqrt{1+4\ln\left(2\right)}}{2};\dfrac{1+\sqrt{1+4\ln\left(2\right)}}{2} \right\}

S=\left\{-2;1 \right\}

S =\varnothing

S=\left\{ -\sqrt{\dfrac{5}{2}};\sqrt{\dfrac{5}{2}} \right\}

S=\left\{ -\sqrt{\dfrac{e^6-1}{2}};\sqrt{\dfrac{e^6-1}{2}} \right\}

S=\left\{\sqrt{\dfrac{e^6-1}{2}} \right\}

S = \left\{ \sqrt{\dfrac{\ln\left(5\right)+1}{3}};-\sqrt{\dfrac{\ln\left(5\right)+1}{3}}\right\}

S = \left\{ \sqrt{\dfrac{\ln\left(5\right)+1}{3}}\right\}

S=\left\{ -\sqrt{\dfrac{5}{3}};\sqrt{\dfrac{5}{3}} \right\}

S=\left\{ \sqrt{\dfrac{5}{3}} \right\}