Dériver une fonction affine composée par une fonction inverse Exercice

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{1}{3} \right\} , f'(x)=\dfrac{−3}{(3x+1)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{1}{3} \right\} , f'(x)= \dfrac{3}{(3x+1)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{1}{3} \right\} , f'(x)= \dfrac{−1}{(3x+1)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{1}{3} \right\} , f'(x)=\dfrac{1}{(3x+1)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{3}{4} \right\} , f'(x)=\dfrac{4}{(−4x+3)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{3}{4} \right\} , f'(x)=\dfrac{−4}{(−4x+3)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{3}{4} \right\} , f'(x)=\dfrac{−2}{(−4x+3)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{3}{4} \right\} , f'(x)=\dfrac{2}{(−4x+3)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{6}{5} \right\} , f'(x)=\dfrac{−5}{(5x−6)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{6}{5} \right\} , f'(x)=\dfrac{5}{(5x−6)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{6}{5} \right\} , f'(x)=\dfrac{−10}{(5x−6)^2}

\forall x \in \mathbb{R} \backslash \left\{ \dfrac{6}{5} \right\} , f'(x)=\dfrac{10}{(5x−6)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{2}{3} \right\} , f'(x)=\dfrac{3}{(−3x−2)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{2}{3} \right\} , f'(x)=\dfrac{−3}{(−3x−2)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{2}{3} \right\} , f'(x)=\dfrac{1}{(−3x−2)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{2}{3} \right\} , f'(x)=\dfrac{−1}{(−3x−2)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{7}{6} \right\} , f'(x)=\dfrac{−6}{(6x+7)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{7}{6} \right\} , f'(x)=\dfrac{−7}{(6x+7)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{7}{6} \right\} , f'(x)=\dfrac{7}{(6x+7)^2}

\forall x \in \mathbb{R} \backslash \left\{ -\dfrac{7}{6} \right\} , f'(x)=\dfrac{6}{(6x+7)^2}